As stated below, random.shuffle doesn't return a new shuffled list; it shuffles the list in place. So you shouldn't say "print random.shuffle (b)" and should instead do the shuffle on one line and print b on …

Aug 28, 2017 · When dealing with regular Python lists, random.shuffle() will do the job just as the previous answers show. But when it come to ndarray (numpy.array), random.shuffle seems to break …

Is there a straightforward way to RETURN a shuffled array in Python rather than shuffling it in place? e.g., instead of x = [array] random.shuffle(x) I'm looking for something like y = shuffle(x)

How shuffle from random works in Python? I ask because it works very fast. When I try to write shuffle it works 1 minute for 10^6 element, but Python shuffle does that in 8 sec?

132 import random x = [1, 2, 3, 4, 5, 6] random.shuffle(x) print x I know how to shuffle a list, but is it possible to shuffle it with a parameter such that the shuffling produces the same result every time? …

Jan 31, 2012 · The random argument is used for specifying (another) random number generator. it's a function expected to return uniform random numbers in the range 0<=x<1 If the same number is …

I'm very new to Python, so bear with me. I would like to run a program that will shuffle a string of integers in a specific range, but without having to input each integer within that range.

Dec 10, 2019 · random.shuffle() is seeded -- Python just takes care of the seeding boilerplate for you. The only time you would do anything different is for reproducibility, not for better randomness. Calling …

2 As mentioned by @jonrsharpe, random.shuffle acts on the list in place. When you append x, you are appending the reference to that specific object. As such, at the end of the loop, k contains ten …

The random.shuffle function calls the random function more than once, so using a lambda that always returns the same value may have unintended effects on the output order.